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day 10 w\o rust

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day10_syntax_scoring/Cargo.toml

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+[package]
+name = "day10_syntax_scoring"
+version = "0.1.0"
+edition = "2021"
+
+# See more keys and their definitions at https://doc.rust-lang.org/cargo/reference/manifest.html
+
+[dependencies]

+ 138 - 0
day10_syntax_scoring/README.md

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+--- Day 10: Syntax Scoring ---
+------------------------------
+
+You ask the submarine to determine the best route out of the deep-sea cave, but it only replies:
+
+
+
+```
+Syntax error in navigation subsystem on line: all of them
+```
+
+*All of them?!* The damage is worse than you thought. You bring up a copy of the navigation subsystem (your puzzle input).
+
+
+The navigation subsystem syntax is made of several lines containing *chunks*. There are one or more chunks on each line, and chunks contain zero or more other chunks. Adjacent chunks are not separated by any delimiter; if one chunk stops, the next chunk (if any) can immediately start. Every chunk must *open* and *close* with one of four legal pairs of matching characters:
+
+
+* If a chunk opens with `(`, it must close with `)`.
+* If a chunk opens with `[`, it must close with `]`.
+* If a chunk opens with `{`, it must close with `}`.
+* If a chunk opens with `<`, it must close with `>`.
+
+
+So, `()` is a legal chunk that contains no other chunks, as is `[]`. More complex but valid chunks include `([])`, `{()()()}`, `<([{}])>`, `[<>({}){}[([])<>]]`, and even `(((((((((())))))))))`.
+
+
+Some lines are *incomplete*, but others are *corrupted*. Find and discard the corrupted lines first.
+
+
+A corrupted line is one where a chunk *closes with the wrong character* - that is, where the characters it opens and closes with do not form one of the four legal pairs listed above.
+
+
+Examples of corrupted chunks include `(]`, `{()()()>`, `(((()))}`, and `<([]){()}[{}])`. Such a chunk can appear anywhere within a line, and its presence causes the whole line to be considered corrupted.
+
+
+For example, consider the following navigation subsystem:
+
+
+
+```
+[({(<(())[]>[[{[]{<()<>>
+[(()[<>])]({[<{<<[]>>(
+{([(<{}[<>[]}>{[]{[(<()>
+(((({<>}<{<{<>}{[]{[]{}
+[[<[([]))<([[{}[[()]]]
+[{[{({}]{}}([{[{{{}}([]
+{<[[]]>}<{[{[{[]{()[[[]
+[<(<(<(<{}))><([]([]()
+<{([([[(<>()){}]>(<<{{
+<{([{{}}[<[[[<>{}]]]>[]]
+
+```
+
+Some of the lines aren't corrupted, just incomplete; you can ignore these lines for now. The remaining five lines are corrupted:
+
+
+* `{([(<{}[<>[]}>{[]{[(<()>` - Expected `]`, but found `}` instead.
+* `[[<[([]))<([[{}[[()]]]` - Expected `]`, but found `)` instead.
+* `[{[{({}]{}}([{[{{{}}([]` - Expected `)`, but found `]` instead.
+* `[<(<(<(<{}))><([]([]()` - Expected `>`, but found `)` instead.
+* `<{([([[(<>()){}]>(<<{{` - Expected `]`, but found `>` instead.
+
+
+Stop at the first incorrect closing character on each corrupted line.
+
+
+Did you know that syntax checkers actually have contests to see who can get the high score for syntax errors in a file? It's true! To calculate the syntax error score for a line, take the *first illegal character* on the line and look it up in the following table:
+
+
+* `)`: `3` points.
+* `]`: `57` points.
+* `}`: `1197` points.
+* `>`: `25137` points.
+
+
+In the above example, an illegal `)` was found twice (`2*3 = *6*` points), an illegal `]` was found once (`*57*` points), an illegal `}` was found once (`*1197*` points), and an illegal `>` was found once (`*25137*` points). So, the total syntax error score for this file is `6+57+1197+25137 = *26397*` points!
+
+
+Find the first illegal character in each corrupted line of the navigation subsystem. *What is the total syntax error score for those errors?*
+
+
+--- Part Two ---
+----------------
+
+Now, discard the corrupted lines. The remaining lines are *incomplete*.
+
+
+Incomplete lines don't have any incorrect characters - instead, they're missing some closing characters at the end of the line. To repair the navigation subsystem, you just need to figure out *the sequence of closing characters* that complete all open chunks in the line.
+
+
+You can only use closing characters (`)`, `]`, `}`, or `>`), and you must add them in the correct order so that only legal pairs are formed and all chunks end up closed.
+
+
+In the example above, there are five incomplete lines:
+
+
+* `[({(<(())[]>[[{[]{<()<>>` - Complete by adding `}}]])})]`.
+* `[(()[<>])]({[<{<<[]>>(` - Complete by adding `)}>]})`.
+* `(((({<>}<{<{<>}{[]{[]{}` - Complete by adding `}}>}>))))`.
+* `{<[[]]>}<{[{[{[]{()[[[]` - Complete by adding `]]}}]}]}>`.
+* `<{([{{}}[<[[[<>{}]]]>[]]` - Complete by adding `])}>`.
+
+
+Did you know that autocomplete tools *also* have contests? It's true! The score is determined by considering the completion string character-by-character. Start with a total score of `0`. Then, for each character, multiply the total score by 5 and then increase the total score by the point value given for the character in the following table:
+
+
+* `)`: `1` point.
+* `]`: `2` points.
+* `}`: `3` points.
+* `>`: `4` points.
+
+
+So, the last completion string above - `])}>` - would be scored as follows:
+
+
+* Start with a total score of `0`.
+* Multiply the total score by 5 to get `0`, then add the value of `]` (2) to get a new total score of `2`.
+* Multiply the total score by 5 to get `10`, then add the value of `)` (1) to get a new total score of `11`.
+* Multiply the total score by 5 to get `55`, then add the value of `}` (3) to get a new total score of `58`.
+* Multiply the total score by 5 to get `290`, then add the value of `>` (4) to get a new total score of `294`.
+
+
+The five lines' completion strings have total scores as follows:
+
+
+* `}}]])})]` - `288957` total points.
+* `)}>]})` - `5566` total points.
+* `}}>}>))))` - `1480781` total points.
+* `]]}}]}]}>` - `995444` total points.
+* `])}>` - `294` total points.
+
+
+Autocomplete tools are an odd bunch: the winner is found by *sorting* all of the scores and then taking the *middle* score. (There will always be an odd number of scores to consider.) In this example, the middle score is `*288957*` because there are the same number of scores smaller and larger than it.
+
+
+Find the completion string for each incomplete line, score the completion strings, and sort the scores. *What is the middle score?*
+
+

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day10_syntax_scoring/example.txt

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+[({(<(())[]>[[{[]{<()<>>
+[(()[<>])]({[<{<<[]>>(
+{([(<{}[<>[]}>{[]{[(<()>
+(((({<>}<{<{<>}{[]{[]{}
+[[<[([]))<([[{}[[()]]]
+[{[{({}]{}}([{[{{{}}([]
+{<[[]]>}<{[{[{[]{()[[[]
+[<(<(<(<{}))><([]([]()
+<{([([[(<>()){}]>(<<{{
+<{([{{}}[<[[[<>{}]]]>[]]

+ 110 - 0
day10_syntax_scoring/input.txt

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+{<<<[<(<{[[[[<<><>>({}())]<<[]{}>{<><>}>]]<({<[]{}>}<[[]{}]{[]<>}>){({{}<>}[<>[]))<({}())<{}<>>>}>]([{[<{}<>
+{{{<(<<{<([[<{[][]}<<><>>>{{(){}}}]<{[{}{}][<><>]}[[[]()][()[]]]>])(<{([[]][<>{}])[([]<>){[][]}]}(([[]()]
+(([{<{<<{((({[()[]]([][])}[{()}(<>)])[<(()<>)>(([])[{}[]])]){{([()()){[]()})}})}({<<[(()<>){()}
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+[{([(({<{<([(({}<>)[{}()])])><{[[{[]<>}<<><>>]<<[]<>><(){}>>]}{{<<(){}>{<>()}>[<{}{}>{<>[]}]}[<[()()]
+<[[[<({[[<{{<(<>())(<><>)>{[(){}][{}<>]}}({({}<>){{}[]}])}[[(<{}{}>[()[]])]{(([][])<()>)[({}())<{}()>
+{[[(<(<{<([[(([]{})[<>()])<<[]>[()[]]>](<{()[]}[[]<>]>{[()<>]([]())})][([<{}<>>[{}[]]]{<[]>(<>)
+<[<[[<<(({[(<[[]]{<>[]}>{(<>())(()())})<({(){}}{[][]})>]([{<()()><[]()>}[{[]()}[[][]>]]{{(())}(({}{})<<>[
+(({<{{[{(<[[[<<>()>][{<>()}[[]<>]]]]{{{{<><>}({}{})}{{[][]}({}[])}}{[{{}<>}{[]()}]}}>{<([[
+<([<{([([[{{[{{}{}}<{}()>]<{{}{}}>}({{(){}}{<>()}}[<(){}>[()()]])}[<{{<>[]}[()()]}{{{}[]}{[]<>}}>]]{[{<
+<{({{[<{<(({[({}<>)[[]<>]]<<[]{}>(()<>)>}))[<{((<>[])[<><>])<((){}][()()]>}{<([]{})(<><>)>}>{(
+{<<<<([{[<[{<<(){}>({}{})>}<<{[][]}{<>()}>({{}()}([]{})))]((({<><>}<{}[]>)({[]()}{<>()}))[[<{}{}>][{[]()
+[(<(<[(<{({[<(<>{})[()()]>[([]{}){[]<>}]]{{<{}{}>(<><>)}<{{}()}((){})>}}<<{{()[]}((){}}}{{
+{<<<[(<([{<<([()()][()])<{[]<>}[<>()]>>[<(()())<<>{}>>({[]{}}([]<>))]>}])>)([([{{{[[[]()](()
+<<({<{<([([[<[(){}]<<><>>><{()[]}[(){}]>]<(<{}[]>){[[]<>](()[])}>][<[<(){}>[{}[]]]({[][]}((){}))>
+{([{{[(<({{<(<[][]>{()()}){[{}()]}><(<<>())<[]{}>){<{}{}>((){})}>}}((<(<<>[]><()()>)><{[[][]]}<[<>
+[(<{{[{[{<([[[{}[]]<<>>]][[(()[])[(){}]]])({([<>[]]({}<>)){([]{})({}[])}}({(())({}[])}<{<>[]}(()[])>))
+({[([(<{<(<<(([][])(()()))({[]()}(<>[]))><({{}()}[[]()])>>)>[<[([{()<>}<[]<>>]([{}<>]{()()}})<[<{}

+ 47 - 0
day10_syntax_scoring/main.py

@@ -0,0 +1,47 @@
+import os, sys
+
+task_dir = os.path.dirname(__file__)
+sys.path.append(f"{task_dir}/..")
+from get_tasks import get_input, check_example, generate_readme
+
+
+def solve(input: list[str]) -> tuple[int, int]:
+
+    braces = {")": "(", "}": "{", "]": "[", ">": "<"}
+    reverse_braces = {"(": ")", "{": "}", "[": "]", "<": ">"}
+    illegal_points = {")": 3, "}": 1197, "]": 57, ">": 25137}
+    completion_points = {")": 1, "}": 3, "]": 2, ">": 4}
+
+    scores = []
+    sum = 0
+
+    for line in input:
+        score = 0
+        stack = []
+        not_corrapted = True
+        for char in line.strip():
+            if char in braces.values():
+                stack.append(char)
+            else:
+                if braces[char] == stack[-1]:
+                    stack.pop()
+                else:
+                    sum += illegal_points[char]
+                    not_corrapted = False
+                    break
+        if not_corrapted:
+            while stack:
+                score = score * 5 + completion_points[reverse_braces[stack.pop()]]
+            scores.append(score)
+    print("The anwer of part1 is:", sum)
+    print("The anser of part2 is:", sorted(scores)[int(len(scores) / 2)])
+    return sum, sorted(scores)[int(len(scores) / 2)]
+
+
+if __name__ == "__main__":
+    input, example = get_input(task_dir, 10)
+
+    check_example(example, solve)
+    solve(input)
+
+    generate_readme(task_dir, 10)

+ 3 - 0
day10_syntax_scoring/src/main.rs

@@ -0,0 +1,3 @@
+fn main() {
+    println!("Hello, world!");
+}

+ 1 - 1
day9_smoke_basin/main.py

@@ -20,7 +20,7 @@ def part1(cave: np.ndarray) -> np.ndarray:
         for j in range(cave.shape[1]):
             if (here := cave[i, j]) == (
                 cave[max(0, i - 1) : i + 2, max(0, j - 1) : j + 2]
-            ).min():
+            ).min() and here != 9:
                 mins = np.append(mins, here)
                 centers = np.vstack([centers, [i, j]])
     centers = np.delete(centers, 0, 0)